3(2x-1)=x^2+10

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Solution for 3(2x-1)=x^2+10 equation: 



3(2x-1)=x^2+10

We move all terms to the left:

3(2x-1)-(x^2+10)=0

We multiply parentheses

6x-(x^2+10)-3=0

We get rid of parentheses

-x^2+6x-10-3=0

We add all the numbers together, and all the variables

-1x^2+6x-13=0

a = -1; b = 6; c = -13;
Δ = b2-4ac
Δ = 62-4·(-1)·(-13)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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